Factorize the following using appropriate identities:

Reliable Education Group
0

 (i) 9x2+6xy+y2

Solution:

9x2+6xy+y= (3x)2+(2×3x×y)+y2

Using identity, x2+2xy+y= (x+y)2

Here, x = 3x

y = y

9x2+6xy+y= (3x)2+(2×3x×y)+y2

= (3x+y)2

= (3x+y)(3x+y)

(ii) 4y2−4y+1

Solution:

4y2−4y+1 = (2y)2–(2×2y×1)+1

Using identity, x2 – 2xy + y= (x – y)2

Here, x = 2y

y = 1

4y2−4y+1 = (2y)2–(2×2y×1)+12

= (2y–1)2

= (2y–1)(2y–1)

(iii)  x2–y2/100

Solution:

x2–y2/100 = x2–(y/10)2

Using identity, x2-y= (x-y)(x+y)

Here, x = x

y = y/10

x2–y2/100 = x2–(y/10)2

= (x–y/10)(x+y/10)

Post a Comment

0Comments

Hello,
May I help you ?

Post a Comment (0)

#buttons=(Ok, Go it!) #days=(20)

Our website uses cookies to enhance your experience. Check Now
Ok, Go it!