Solution:
Let p(x) = x3−ax2+6x−a
x−a = 0
∴x = a
Remainder:
p(a) = (a)3−a(a2)+6(a)−a
= a3−a3+6a−a = 5a
Find the remainder when x^3−ax^2+6x−a is divided by x-a.
April 23, 2022
0
Solution:
Let p(x) = x3−ax2+6x−a
x−a = 0
∴x = a
Remainder:
p(a) = (a)3−a(a2)+6(a)−a
= a3−a3+6a−a = 5a
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