Solution:
It is given that the sides of the wall as 15 m, 11 m and 6 m.
So, the semi perimeter of triangular wall (s) = (15+11+6)/2 m = 16 m
Using Heron’s formula,
Area of the message =
= √[16(16-15)(16-11) (16-6)] m2
= √[16×1×5×10] m2 = √800 m2
= 20√2 m2
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