Solution:
Radius (r) of heap = (10.5/2) m = 5.25
Height (h) of heap = 3m
Volume of heap = (1/3)πr2h
= (1/3)×(22/7)×5.25×5.25×3
= 86.625
The volume of the heap of wheat is 86.625 m3.
Again,
= (22/7)×5.25×6.05
= 99.825
Therefore, the area of the canvas is 99.825 m2.
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