Solution:
Inner radius of circular well, r = 3.5/2m = 1.75m
Depth of circular well, say h = 10m
(i) Inner curved surface area = 2πrh
= (2×(22/7 )×1.75×10)
= 110 m2
Therefore, the inner curved surface area of the circular well is 110 m2.
(ii)Cost of plastering 1 m2 area = Rs.40
Cost of plastering 110 m2 area = Rs (110×40)
= Rs.4400
Therefore, the cost of plastering the curved surface of the well is Rs. 4400.
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